Ascorbic acid (vitamin C, C6H8O6) is a water-soluble vitamin. A solution containing 83.3 g of ascorbic acid dissolved in 210. g of water has a density of 1.23 g/mL at 55°C
Calculate the molarity of ascorbic acid in this solution.
i got 2.77 but its wrong
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To calculate the molarity of ascorbic acid in the solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's find the moles of ascorbic acid in the solution:
Moles of ascorbic acid = mass of ascorbic acid / molar mass of ascorbic acid
The molar mass of ascorbic acid (C6H8O6) is:
(6 * atomic mass of carbon) + (8 * atomic mass of hydrogen) + (6 * atomic mass of oxygen)
= (6 * 12.01 g/mol) + (8 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 8.08 g/mol + 96.00 g/mol
= 176.14 g/mol
Now, let's calculate the moles of ascorbic acid:
Moles of ascorbic acid = 83.3 g / 176.14 g/mol
Next, we need to convert the mass of water to volume using density:
Density = mass / volume
Rearranging the formula, we have:
Volume = mass / density
Volume of water = 210 g / 1.23 g/mL
Now, we need to convert the volume from mL to L:
Volume of water (in liters) = (210 g / 1.23 g/mL) * (1 mL / 1 cm³) * (1 cm³ / 1 mL) * (1 L / 1000 cm³)
Finally, we can calculate the molarity:
Molarity of ascorbic acid = moles of ascorbic acid / volume of solution (in liters)
Substituting the values calculated:
Molarity = (83.3 g / 176.14 g/mol) / [(210 g / 1.23 g/mL) * (1 mL / 1 cm³) * (1 cm³ / 1 mL) * (1 L / 1000 cm³)]
Make sure to perform all the calculations accurately, and you should get the correct molarity of ascorbic acid for the given solution.