Homework Help: Chemistry

Posted by Tawnya on Monday, January 21, 2013 at 1:03am.

Can someone please help me out here?
I've tried several times and i keep getting the wrong answer :( lol
A small crucible is filled with 100.00 mL of n-hexadecane (MW (226.44 g/mol), density (0.7703 g/mL))
and 2.10 L of 7-octenyltrichlorosilane (MW (245.65 g/mol), density (1.07 g/mL)).
Calculate the concentration in mM of the reagent in solution

Chemistry - anonymous, Tuesday, January 22, 2013 at 8:27pm
Number of moles of n-hexadane is

100 mL * (0.7703 g/mL) * (1 mol / 226.44 g)

mL and g units cancel

= 100 * (0.7703/226.44) moles n-hexadane

The total volume of the final solution is 100 mL + 2100 mL = 2200 mL = 2.2 L

The concentration of n-hexadane in mM is

100 * (0.7703/226.44) M / 2.2L * (1000 mM / M)

If n-hexadane is your reagent, then this is the final answer; otherwise repeat this type of calculation to find the final concentration of 7-ocenyltrichlorosilane in solution.

Answer this Question

Related Questions

Chemistry - "Suppose some sort of clamp is applied to hold an electron ...
Chemistry - "Suppose some sort of clamp is applied to hold an electron ...
Math - Hi, I am getting very frustrated. I am doing an online homework for ...
algebra 1 - -2/3z=-4/9 i tried to solve, but i keep on getting the wrong answer...
chem - Calculate the solubility of magnesium hydroxide (Mg(OH)2), ksp=1.1x10^-11...
Math - Can someone please help me with this question? I have tried to figure it ...
Math - (7.66 • 10^2)(6.29 • 10^-4) answer then convert to scientific ...
PHYSICS - Could u help with physics hw! i keep trying but i keep getting the ...
Maths - 3x - 6 = 3x/4 With my working out I got x = 24/15 The answers say that x...
chemistry - A sample of 690. moles of O2 reacted according to the balanced ...

For Further Reading

First Name:
School Subject:
Answer: