A pendulum and a mass spring system are both undergoing simple harmonic motion on Earth (use g = 10 N/kg). It is observed that every time the pendulum goes back and forth, the spring has gone up and down 12 times. If the pendulum has a length of 4 meters and the mass is 100 g, determine:
a)The period of the pendulum?
b)The period of the spring-mass system?
c)the spring constant of the spring?
d)On the moon, how many times will the mass bounce up and down when the pendulum swings back and forth one time?
Physics - anonymous, Tuesday, January 22, 2013 at 8:17pm
The period of a pendulum is 2*PI*(L/g)^0.5, where L = 4 meters; g = 10 m/s^2
The period of the spring is 1/12 of the answer in a)
c: 2*PI/Tspring = (k/m)^0.5
Tspring is the period of the spring found in part b, m is the mass = 0.1 kg. Solve for k, the spring constant of the spring.