Posted by **Anthony** on Sunday, January 20, 2013 at 11:35pm.

A pendulum and a mass spring system are both undergoing simple harmonic motion on Earth (use g = 10 N/kg). It is observed that every time the pendulum goes back and forth, the spring has gone up and down 12 times. If the pendulum has a length of 4 meters and the mass is 100 g, determine:

a)The period of the pendulum?

sec

b)The period of the spring-mass system?

sec

c)the spring constant of the spring?

N/m

d)On the moon, how many times will the mass bounce up and down when the pendulum swings back and forth one time?

times

- Physics -
**anonymous**, Tuesday, January 22, 2013 at 8:17pm
The period of a pendulum is 2*PI*(L/g)^0.5, where L = 4 meters; g = 10 m/s^2

The period of the spring is 1/12 of the answer in a)

c: 2*PI/Tspring = (k/m)^0.5

Tspring is the period of the spring found in part b, m is the mass = 0.1 kg. Solve for k, the spring constant of the spring.

## Answer This Question

## Related Questions

- physics - A pendulum and a mass spring system are both undergoing simple ...
- PHYsics !! - a) What do you understand by Simple Harmonic Motion? b) A simple ...
- Physics - A simple pendulum has mass 1.14 kg and length 0.760 m. (a) What is ...
- physics - The length of a simple pendulum is 0.79m and the mass of the particle ...
- Physics - Two different simple harmonic oscillators have the same natural ...
- Physics - A simple pendulum is swinging back and forth through a small angle, ...
- Physics Help please - The free-fall acceleration on Mars is 3.7 m/s2. (a) What ...
- physics - The inverted pendulum shown consists of a uniform rod of length L and ...
- physics help! - Objects of equal mass are oscillating up and down in simple ...
- physics - A particle vibrates in Simple Harmonic Motion with amplitude. What ...

More Related Questions