Posted by ashlee on Sunday, January 20, 2013 at 8:42am.
Wc = m*g = 5kg * 9.8N/kg = 49 N, = Wt.
of crate.
Fp = 49*sin25 = 20.3 = Force parallel to
ramp.
Fv = 49*cos25 = 44.4 N. = Force perpendicular to ramp.
Fs = u*Fv = 0.5*44.4 = 22,2 N. = Force
of static friction.
Related Questions
physics - a 5-kg crate is resting on a horizontal plank. the coefficient of ...
Physics - A student wants to determine the coefficients of static friction and ...
PHYSICS - A student wants to determine the coefficients of static friction and ...
Physics - A crate of potatoes of mass 23.0 kg is on a ramp with angle of incline...
physics - Once a 28 kg crate is in motion on a horizontal floor, a ...
physics - Once a 15 kg crate is in motion on a horizontal floor, a ...
Physics - Once a 15 kg crate is in motion on a horizontal floor, a ...
physics - A 100 N force is applied to the side of a crate resting on a level ...
physics - A student wants to determine the coefficients of static friction and ...
physics - A dockworker loading crates on a ship finds that a 21-kg crate, ...
For Further Reading