Posted by Luellen on .
A boy's hand pushes a ball through a vertical distance of 1.45 m as he throws the ball straight upward. Once the ball leaves his hand it travels an additional 22 m (straight up) before returning to earth. Find the acceleration of the ball while it was in the boy's hand
You need to find the vertical velocity of the ball at launch.
The PE at the top=KE at launch
mg*22=1/2 m v^2
v= sqrt (2*g*22) m/s
now, considering just the period throwing
solve for a