A 100 lb bag of fertizer with an analysis of 6-12-24 would provide ___ lbs of P.
http://en.wikipedia.org/wiki/NPK_rating
To determine the number of pounds of P (Phosphorus) in a 100 lb bag of fertilizer with an analysis of 6-12-24, we need to understand what the numbers in the analysis represent.
In a fertilizer analysis, the three numbers typically represent the percentage by weight of three primary nutrients: Nitrogen (N), Phosphorus (P), and Potassium (K). The numbers are commonly referred to as the N-P-K ratio.
In this case, the analysis of 6-12-24 means that the fertilizer contains 6% Nitrogen, 12% Phosphorus, and 24% Potassium.
To find the number of pounds of P in a 100 lb bag, we can use the following steps:
Step 1: Calculate the percentage of Phosphorus in the bag of fertilizer:
Phosphorus percentage = 12/100 = 0.12 (or 12%)
Step 2: Determine the weight of Phosphorus in the bag:
Weight of Phosphorus = Phosphorus percentage * Total weight of bag
Weight of Phosphorus = 0.12 * 100 lbs
Weight of Phosphorus = 12 lbs
Therefore, a 100 lb bag of fertilizer with an analysis of 6-12-24 would provide 12 lbs of Phosphorus.