How many cm3 solution of 36% HCl with density 1.183g/cm3 should be taken to prepare 250cm3 solution with concentration of 0.215 g/dm3.

First determine the concn of the 36% HCl then use the dilution formula to make whatever concn you need from that.

1.183 g/cc x 1000 cc x 0.36 x (1 mol/36.5g) = ?M HCl for the 36% stuff. You should get approximately 12M
I would convert 0.215 g to mols; 0.215/36.5 = about 0.0059

Then c1v1 = c2v2
12M x v(in cc) = 0.0059 x 250cc
Solve for v.

DrBob222 can you explain one by one.. i didn't get it

First you want to determine the molarity of the 36% HCl. M = mols/L.

The density is 1.183 g/cc.
How much does 1000 mL weigh? That's 1.183 x 1000 mL = ?grams = mass 1 L.
How much of that is HCl? 36%. So
? grams x 0.36 = ? g HCl. The rest of it is water.
How many mols HCl is that?
mols HCl = grams HCl/molar mass HCl and molar mass HCl is about 36.5.

Then follow the c1v1 = c2v2 I gave above.

DrBob222 thanks for answering.Can it be solved this way:

0.250dm3 x 0.215g/dm3 / 1.183g/cm3 x 0.36 = 0.1262 cm3

To find the volume of the 36% HCl solution required to prepare a 250cm3 solution with a concentration of 0.215 g/dm3, we need to use the formula:

C1V1 = C2V2

where:
C1 = concentration of the concentrated solution (36% HCl), given as a mass/volume percentage
V1 = volume of the concentrated solution (unknown)
C2 = concentration of the diluted solution (0.215 g/dm3)
V2 = volume of the diluted solution (250 cm3)

First, convert the given concentrations to the same unit. Since the concentration of the concentrated solution is given as a mass/volume percentage, we need to convert it to g/dm3. To do this, multiply the concentration by the density:

(36 g/100 cm3) * (1.183 g/cm3) = 42.588 g/dm3

Now, we can substitute the values into the formula:

(42.588 g/dm3) * V1 = (0.215 g/dm3) * (250 cm3)

Solving for V1:

V1 = (0.215 g/dm3 * 250 cm3) / (42.588 g/dm3)
V1 = 1.273 cm3

Therefore, you should take approximately 1.273 cm3 of the 36% HCl solution to prepare the 250 cm3 solution with a concentration of 0.215 g/dm3.