Posted by Anonymous on Saturday, January 19, 2013 at 1:29am.
Select the larger value of reduction potential, reverse it and change the sign. That will be Zn^2+ + 2e ==> Zn Eored = -0.76
Zn ==> Zn^2++ 2e Eo ox = 0.76v
Co^2+ + 2e ==> Co Eo red = -.28v
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Zn +Co^2+ ==>Zn2+ + Co is cell rxn.
Eocell = Eoox + Eored = +0.76 + (-0.28) = ? is cell voltage.
That anode is where oxidation occurs. Which of the two half cells I've written above is oxidation(loss of electrons)? The cathode of course is the other one.
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