Posted by liz on Friday, January 18, 2013 at 9:23pm.
amount invested at 12% --- x
amount invested at 10% --- 15000-x
.12x + .10(15000-x = 1600
12x + 10(15000-x) = 160000
12x + 150000 - 10x = 160000
2x = 10000
x = 5000
so $5000 invested at 12% and $10000 invested at 10%
check:
.12(5000) + .1(10000) = 1600
YUP!
Related Questions
Algebra 1 - Ms. Buxx invested a total of $2000 in two saving accounts. The first...
Problem Solving - Johnny has two bank accounts. One pays 7% interest and the ...
math - Suppose $500 is divided into two bank accounts. One account pays 15% ...
mat h - ms. buxx invested a total of $2000 in two savings accounts. The first ...
accounting - P9-4A (a-d) Wall Inc. uses the allowance method to estimate ...
Math - You invested $14,000 in two accounts paying 5% and 9% annual interest, ...
algebra - two investments were made totaling $15,000. for a certain year these ...
accounting - Exercise 9-13: Accounts receivable turnover L.O. A1 The following ...
math - you invested $4000 in two accounts paying 2% and 9% annual interest, ...
accounting - I was given gross accounts receivable $15,200,000 and $17,600,000 ...
For Further Reading