Posted by **ugh** on Friday, January 18, 2013 at 9:22pm.

A charge q1 = 5 ìC is at the origin. A second charge q2 = -3 ìC is on the x-axis, 0.8 m from the origin. The electric field at a point on the y-axis, 0.5 m from the origin is:

I don't understand the question please help . Thanks for reading

- Physics -
**Elena**, Saturday, January 19, 2013 at 6:29am
q₁ = 5 μC =5•10⁻⁶ C,

q₂ = - 3 μC = - 3•10⁻⁶ C,

r₁ =0.5 m,

r₂ = 0.8 m.

k =9•10⁹ N•m²/C²

E₁=k•q₁/ r₁², (directed ↑)

E₂ = k•q₂/ r₂², (directed ↑)

vector E= vector E₁+vectorE₂

The magnitude of vector E is directed ↗ and is calculated using the cosine law.

tanα =0.8/0.5=1.6

α =58⁰

E=sqrt{E₁²+E₂²-2E₁E₂cosα} = …

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