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March 29, 2017

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A charge q1 = 5 ìC is at the origin. A second charge q2 = -3 ìC is on the x-axis, 0.8 m from the origin. The electric field at a point on the y-axis, 0.5 m from the origin is:

I don't understand the question please help . Thanks for reading

  • Physics - ,

    q₁ = 5 μC =5•10⁻⁶ C,
    q₂ = - 3 μC = - 3•10⁻⁶ C,
    r₁ =0.5 m,
    r₂ = 0.8 m.
    k =9•10⁹ N•m²/C²
    E₁=k•q₁/ r₁², (directed ↑)
    E₂ = k•q₂/ r₂², (directed ↑)
    vector E= vector E₁+vectorE₂
    The magnitude of vector E is directed ↗ and is calculated using the cosine law.
    tanα =0.8/0.5=1.6
    α =58⁰
    E=sqrt{E₁²+E₂²-2E₁E₂cosα} = …

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