Posted by **raghunath laguri** on Friday, January 18, 2013 at 5:07pm.

differentiate of y=|sinx|+|cosx|

- math -
**Steve**, Friday, January 18, 2013 at 5:35pm
if y = sinx, y' = cosx

for sinx < 0, |sinx| = -sinx

so, y' = cosx * |sinx|/sinx, or

y' = |sinx| cotx

similarly for cosx

## Answer this Question

## Related Questions

- Trig........ - I need to prove that the following is true. Thanks (cosx / 1-sinx...
- Pre-Calc - Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= ...
- Trigonometry Check - Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [...
- Math - Verify the identity . (cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant ...
- Trigonometry. - ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! ...
- Math - Pre- Clac - Prove that each of these equations is an identity. A) (1 + ...
- trigonometry - can i use factoring to simplify this trig identity? the problem ...
- Mathematics - Trigonometric Identities - Prove: (tanx)(sinx) / (tanx) + (sinx...
- Math - Im really struggling with these proving identities problems can somebody ...
- maths - trigonometry - I've asked about this same question before, and someone ...

More Related Questions