Posted by raghunath laguri on Friday, January 18, 2013 at 5:07pm.
differentiate of y=sinx+cosx

math  Steve, Friday, January 18, 2013 at 5:35pm
if y = sinx, y' = cosx
for sinx < 0, sinx = sinx
so, y' = cosx * sinx/sinx, or
y' = sinx cotx
similarly for cosx
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