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March 31, 2015

March 31, 2015

Posted by **yoshii** on Friday, January 18, 2013 at 11:27am.

- Math -
**Reiny**, Friday, January 18, 2013 at 12:11pmIf (a,b,c) is any point, then its distance to

Ax + By +Cz + D =0 is

**|Aa + Bb + Cc + D|/√(A^2 + B^2 + C^2)**

= |2(1) - 2(0) + 1(-3) + 7|/√(1 + 0 + 9)

= 6/√10

or

= 6√10/10 = 3√10/5

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