find the distance between M(1; 0; -3) point and 2x-2y+z+7=0 plane
If (a,b,c) is any point, then its distance to
Ax + By +Cz + D =0 is
|Aa + Bb + Cc + D|/√(A^2 + B^2 + C^2)
= |2(1) - 2(0) + 1(-3) + 7|/√(1 + 0 + 9)
= 6/√10
or
= 6√10/10 = 3√10/5