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April 16, 2014

April 16, 2014

Posted by **yoshii** on Friday, January 18, 2013 at 10:48am.

Lim (49x^2-25)/(7x-5)

x->5/7

- Math -
**Steve**, Friday, January 18, 2013 at 10:50amsince 79x^2 - 25 = (7x-5)(7x+5)

f(x) = 7x+5 for x ≠ 5/7

so, the limit is 7(5/7) + 5 = 10

- Math -
**yoshii**, Friday, January 18, 2013 at 10:52amthank u

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