Post a New Question

Physics

posted by on .

A 3.6 kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant, horizontal force of 18.2 N. Find the speed of the block after it has moved 2.7 m. Answer in units of m/s

  • Physics - ,

    Vi=0, D=2.7m, and Vf=?. Use F=ma= 18.2N=3.6Kg*(a) and solve for the acceleration (a). Once you have solved for a. Plug in the numbers into one of the kinematic equations Vf^2=Vi^2+2ad. I haven't worked out the math, but you should het the right answer.

  • Physics - ,

    F=MA>
    sqrt(2AX)
    distance is X

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question