Thursday

April 24, 2014

April 24, 2014

Posted by **Rachael** on Friday, January 18, 2013 at 1:24am.

- AP Calculus -
**Steve**, Friday, January 18, 2013 at 4:38amthe distance d between the ships is

d^2 = x^2 + y^2

2d dd/dt = 2x dx/dt + 2y dy/dt

at 3:00 am, x=30 and y=10, d=10√10

20√10 dd/dt = 2(30)(15) + 2(10)(10)

dd/dt = 1100/10√10 = 110/√10 = 11√10

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