Posted by Rachael on Friday, January 18, 2013 at 1:24am.
the distance d between the ships is
d^2 = x^2 + y^2
2d dd/dt = 2x dx/dt + 2y dy/dt
at 3:00 am, x=30 and y=10, d=10√10
20√10 dd/dt = 2(30)(15) + 2(10)(10)
dd/dt = 1100/10√10 = 110/√10 = 11√10
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