Monday

March 2, 2015

March 2, 2015

Posted by **Rachael** on Friday, January 18, 2013 at 1:24am.

- AP Calculus -
**Steve**, Friday, January 18, 2013 at 4:38amthe distance d between the ships is

d^2 = x^2 + y^2

2d dd/dt = 2x dx/dt + 2y dy/dt

at 3:00 am, x=30 and y=10, d=10√10

20√10 dd/dt = 2(30)(15) + 2(10)(10)

dd/dt = 1100/10√10 = 110/√10 = 11√10

**Answer this Question**

**Related Questions**

calculus - We know this is a piecewise function and we solved the first part, ...

Math - "A ship leaves port on a bearing of 34.0 degrees and travels 10.4 mi. ...

Maths- calculus - Two ships leave different ports A and B 100 miles apart at ...

I NEED URGENT HELP!!! - A ship leaves port at 1:00 P.M. and sails in the ...

geometry - A ship leaves port and heads due east at a rate of 32 miles per hour...

trig - Help! Ships A and B leave port at the same time and sail on straight ...

Trigonometry - If a ship leaves port at 9:00 a.m. and sails due south for 3 ...

math - four diesel ships left a port at noon;january2,1953.the first ship ...

Trig - Two ships leave the same port at 7.am. The first ship sails towards ...

Trigonometry - A ship leaves port at 2:00 pm and sails in the direction S34 ...