Saturday

December 20, 2014

December 20, 2014

Posted by **Becca** on Friday, January 18, 2013 at 12:20am.

1. -4/Square root 20

2. Square root of 125/12n^3

3. Square root 10-3 /Square root 3 +Square root 2

4. 7+ square root 6 /3-3 square root 2

- Algebra -
**Steve**, Friday, January 18, 2013 at 4:48am-4/√20 = -4√20/20 = -1/5 √20 = -2/5 √5

√(125/n^3) = √(25/n^2) √(5/n) = 5/n √(5/n)

= 5/n √(5n/n^2) = 5/n^2 √(5n)

(√10-3)/(√3+√2)

= (√10-3)(√3-√2) / (3-2)

= √30-3√3-√20+3√2

= 3√2-3√3-2√5+√30

(7+√6)/(3-√2)

= (7+√6)(3+√2) / (9-2)

= (21+3√6+7√2+√12)/7

= 1/7 (21 + 3√6 + 7√2 + 2√3)

- Algebra -
**corrine**, Saturday, January 19, 2013 at 8:49pm8*/81-6/16

please help

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