1. How would you take 1L of an existing solution with a concentration of 1M and use it to make a new solution of 0.1 M? Be specific.

Tell me the process..... What would you do....ex: I would pour this into that .......
2. Would it be possible to easily create a 2 M solution from 100 mL of 1 M solution? Explain why or why not?

You can do this one of two ways.

1. Use reason. You have 1M, you want 0.1M which means you want the final solution to be 1/10 the original so dilute the solution by 10. That means dumping, quantitatively, the 1L into a 10L volumetric flask and adding water to the 10 L mark.

2. Use the dilution formula for these.
c1v1 = c2v2
c = concn
v = volume
1L*1M = xL*0.1M
xL = 1/0.1 = 10L final volume.

2. I've answered these before. You can make a more concentrated solution by boiling away the water. You want 1M to become 2M so you must boil away half the water. Use the dilution formula if you wish.
1M*100mL =xmL x 2M
xmL = (1M x 100 mL/2M)
xmL = 50 mL . You have 100 to begin you want the final volume to be 50 mL.

You would dilute the solution using MV=MV. Since you already have 1L of a 1M solution, you need to use the equation to calculate 0.1M. The answer will be 100L solution but you will only need to add 99L of H2O for every 1L of the solution. You will get 100L using the equation, but remember you already have 1L so you only need 99L of H20. You can convert this to mL if needed (i.e. 1mL of 1M solution for very 99mL of H20), and as far as I know, unless you can use distillation to separate 50mL of pure H20 from your 100mL of 2M solution, you will not be able to get a 2M solution from a 1M.

Using MV = MV I get

1M*1L = 0.1M*V and
V = (1*1/0.1) = 10 L and not 100 L.

In addition to the wrong answer, I think it is unwise to talk about taking 1L and adding 99 L to make 100 L. Although it may be close (in fact even VERY close), it gives the impression that all solution volumes are additive and that isn't so. You do this right by "adding to a final volume of 10L or in the case of 100 L to a final volume of 100 L."

Sorry, it should read 10L, not 100L and 9L not 99L. Also, DrBob22 is right you can boil/distill 50mL of water, but only if they do not have the same boiling point, but the answer is to add 9L not 10L.

1. To make a new solution of 0.1 M from a 1 M solution, you need to dilute the existing solution with a certain amount of solvent (usually water). Here's the step-by-step process:

- Determine the volume of the new solution you want to make. Let's assume you want to make 1 liter (1000 mL) of the new solution.
- Using a volumetric flask or a measuring cylinder, measure out 1000 mL of distilled water (solvent) and pour it into a clean container.
- Next, take the 1 M solution and pour 100 mL of it (which contains 0.1 moles of solute) into the container with the water.
- Mix the solution thoroughly to ensure proper mixing of the solute (substance dissolved in the solution) with the solvent.

By diluting the 1 M solution to a final volume of 1000 mL with water, you've effectively created a new solution with a concentration of 0.1 M.

2. It would be possible to create a 2 M solution from a 100 mL of 1 M solution, but it would require additional solute (the substance being dissolved).

Here's why:

- A 1 M solution means that it contains 1 mole of solute dissolved in 1 liter of solution (1000 mL).
- To create a 2 M solution from a 100 mL of 1 M solution, you would need to double the amount of moles of the solute.
- Since you have 100 mL of 1 M solution, you have 0.1 moles of solute. To create a 2 M solution, you would need to add another 0.1 moles of the solute.
- So, you would need an additional 100 mL of the solute to create a 2 M solution. Simply adding more solvent (water) would not increase the concentration.

Therefore, you would need more solute to increase the concentration to 2 M, and simply diluting the existing 1 M solution would not achieve that concentration.