Posted by Sierra on Thursday, January 17, 2013 at 7:10pm.
Heat gained by aluminum equals heat lost by copper. Let T be the final equilibrium temperature of both.
The heat gain of each metal is
Q = M*C*(T2 - T1). It heat is lost, that number is negative
2.6*0.22*(T-13) = 10.2*0.093*(93-T)
Solve for T.
0.572T - 7.436 = 88.22 - 0.9486 T
1.5206 T = 95.65
T = 63 C
why is the heat lost by the metal sample (Ql)equal to he heat gained by the water in the calorimeter (QG)?
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