Posted by John on Thursday, January 17, 2013 at 3:26pm.
55.34g/mol^3
a=2.77 Å= 2.77•10⁻⁸ cm.
The BCC-cell volume is
V=a³=(2.77•10⁻⁸)³ = 2.13•10⁻²³ cm³.
Density ρ =8.65g/cm³ per unit cell.
Avogadro´s number N₀=6.022•10²³ mol⁻¹.
The number of atoms in the BCC unit cell are calculated
as follows:
1 × 1 = 1 center atom
8 × (1/8) = 1 corner atom
=> n=2 total atoms
Atomic weight = N₀•V• ρ/n =
=6.022•10²³•2.13•10⁻²³•8.65/2 = 55.34 g/mol³
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