an investor invested a total of 1,100 in two mutual funds. One fund earned a 5% profit while the other earned a 2% profit. If the investor's total profit was 49.00 how much invested in each fund?

sorry sandy idk how to do your problem. I did try though :( could you please take a look at mine right below yours though and see if you could tell me how to do it?

amount invested at 5% ---- x

amount invested at 2% ----- 1100 -x

.05x + .02(1100-x) = 49
.05x + 22 - .02x = 49
.03x = 27
x = 27/.03 = 900

invested at 5% = 900
invested at 2% = 200


check: 900+200=1100
.05(900) +.02(200) = 49

all is good!

x + y = 1,100

a + b = 49
(x+5%) + (y+2%) = 1,149

That's all I could take from the question. Now how you solve and get the answer is beyond me.

Ahh makes much more sense when Reiny did it. I remember learning this in algebra. I have a tendency to give everything its own variable, which makes the problem impossible to solve i guess.

To find out how much was invested in each mutual fund, we can set up a system of equations based on the given information.

Let's assume the amount invested in the first mutual fund is 'x' dollars, and the amount invested in the second mutual fund is 'y' dollars.

According to the problem, the investor invested a total of $1,100 in the two mutual funds. So we can write the equation:

x + y = 1,100

We also know that the first fund earned a 5% profit and the second fund earned a 2% profit, with a total profit of $49. To calculate the profit for each fund, we can multiply the amount invested in each fund by the respective profit percentage:

Profit from the first fund = 0.05 * x
Profit from the second fund = 0.02 * y

We can set up another equation based on the total profit earned by the investor:

0.05 * x + 0.02 * y = 49

Now, we can solve this system of equations to find the values of 'x' and 'y'.

Using the substitution or elimination method, we can solve the system of equations to find the values of 'x' and 'y'.