Posted by **Anonymous** on Thursday, January 17, 2013 at 1:55am.

A car enters the freeway with a speed of 6.9

m/s and accelerates uniformly for 3.3 km in

2.8 min.

How fast is the car moving after this time?

Answer in units of m/s

- physics -
**Anonymous**, Saturday, January 19, 2013 at 4:39pm
t = 2.8min * 60s/min = 168 s.

d = Vo*t + 0.5a*t^2 = 3300 m.,

6.9*168 + 0.5a*(168)^2 = 3300

1159 + 14112a = 3300

14112a = 3300-1159 = 2141

a = 0.152 m/s^2.

V = Vo + at = 6.9 + 0.152*168=25.5 m/s.

- physics -
**Henry**, Saturday, January 19, 2013 at 4:44pm
oops! It is Henry Not anonymous.

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