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solve:
4x + 6y = 1/8 and 3x + 7y = 1/10

  • math - ,

    4 x + 6 y = 1 / 8

    -

    3 x + 7 y = 1 / 10
    _________________________


    x - y = 1 / 8 - 1 / 10

    x - y = 5 / 40 - 4 / 40

    x - y = 1 / 40 Add y to both sides

    x - y + y = 1 / 40 + y

    x = y + 1 / 40


    4 x + 6 y = 1 / 8

    4 ( y + 1 / 40 ) + 6 y = 1 /8

    4 y + 4 / 40 + 6 y = 1 / 8

    10 y + 1 / 10 = 1 / 8 Subtract 1 / 10 to both sides

    10 y + 1 / 10 - 1 / 10 = 1 / 8 - 1 / 10

    10 y = 5 / 40 - 40 / 40

    10 y = 1 / 40 Dvide both sides by 10

    y = 1 / 400


    x = y + 1 / 40

    x = 1 / 400 + 1 / 40

    x = 1 / 400 + 10 / 400

    x = 11 / 400


    Solutions :

    x = 11 / 400

    y = 1 / 400


    Proof :

    3 x + 7 y = 1 / 10

    3 * 11 / 400 + 7 * 1 / 400 = 1 / 10

    33 / 400 + 7 / 400 = 1 / 10

    40 / 400 = 1 / 10

    1 / 10 = 1 / 10

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