Posted by **shantel** on Thursday, January 17, 2013 at 12:03am.

A pilot flies her route in two straight-line segments. The displacement vector A for the first segment has a magnitude of 246 km and a direction 30.0o north of east. The displacement vector B for the second segment has a magnitude of 178 km and a direction due west. The resultant displacement vector is R = A + B and makes an angle è with the direction due east. Using the component method, find (a) the magnitude of R and (b) the directional angle è.

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**Henry**, Friday, January 18, 2013 at 6:46pm
a. R = 240km @ 30o+178km @ 180o

X = 240*cos30 + (-)178 = 29.8 km.

Y = 240*sin30 = 120 km.

R^2 = X^2 + Y^2 = (29.8)^2+(120)^2=15288

R = 123.6 km.

tanA = Y/X = 120/29.8 = 4.03.

A = 76.1o North of East = Direction

- physics -
**Henry**, Friday, January 18, 2013 at 6:57pm
Correction: Change 240 km to 246 km and redo all calculations.

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