The length of a rectangle is 5 inches greater than the width. The sum of the length and width is 41 inches. Find the length and width of the rectangle.
Well I would take 41 - 5 to get 36 and half of 36 is 18 so the width is 18 and the length is 18 + 5, 23.
Is 41 inches the perimeter? Or is 41 just the sum of one length plus one width?
To find the length and width of the rectangle, let's set up a system of equations.
Let's assume that the width of the rectangle is x inches.
Since the length is 5 inches greater than the width, we can say that the length is (x + 5) inches.
The sum of the length and width is 41 inches, so we can write the equation:
x + (x + 5) = 41
Now let's solve for x:
2x + 5 = 41
2x = 41 - 5
2x = 36
x = 36/2
x = 18
So, the width of the rectangle is 18 inches.
Now we can find the length of the rectangle by substituting the value of x back into our equation:
Length = x + 5 = 18 + 5 = 23 inches
Therefore, the length of the rectangle is 23 inches and the width is 18 inches.