Posted by **Kyle** on Wednesday, January 16, 2013 at 8:49pm.

Calculate the radius of a vanadium atom, given that V has a BCC crystal structure, a density of 5.96 g/cm3, and an atomic weight of 50.9 g/mol.

I used this equation:

density = (2)*(atomic weight) / (volume of unit cell)*(Avagodro's #)

rearranged to find the volume of the unit cell, V_c.

Then I used the relation:

V_c = a^3 = (4R/sqrt(3))^3

V_c = 64R^3/3sqrt(3)

to find the radius R.

I got R = 1.3x10^-8

They want answers in nm so I should get 0.13nm?

## Answer This Question

## Related Questions

- Chemistry - Calculate the radius of a vanadium atom, given that V has a BCC ...
- Biomaterials - What is the theoretical density of tantalum (Ta) with the ...
- Science/math - BCC crystal structure, atomic radius of .1363, and an atomic ...
- science - Some hypothetical metal has the simple cubic crystal structure. If its...
- chemistry - The ionic radii of Na+ (atomic weight 22.99) and Cl- (atomic weight...
- chemistry - a metal crystallizes in the face centered cubic crystal structure ...
- chemistry - Is the calculation of percentage of each atom within a Body centered...
- Inorganic Chemistry - The atoms in barium metal are arranged in a body centered ...
- Chemistry - the density of an unknown metal is 2.64 g/cm^3 and its atomic radius...
- Chemistry - Determine for solid manganese (Mn) the following: What is the atomic...

More Related Questions