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Find the magnitude and direction of the equilibrant of two forces, one being horizontal pull of 18 N and the other a pull of 23 N at 50 degrees to the 12 N force.

  • Mechanics....Urgent!! -

    Let the 18N force be at direction 000, and the 23N force be at direction 050.

    Hmm. Where is the 12 N force. Something here is wrong.

    Anyway, add the two forces. Then take the negative of them. My preference is to break the forces into components 90 deg apart, then add using trig.

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