Posted by joe on Wednesday, January 16, 2013 at 8:44pm.
Let the 18N force be at direction 000, and the 23N force be at direction 050.
Hmm. Where is the 12 N force. Something here is wrong.
Anyway, add the two forces. Then take the negative of them. My preference is to break the forces into components 90 deg apart, then add using trig.
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