Wednesday

September 17, 2014

September 17, 2014

Posted by **Cass** on Wednesday, January 16, 2013 at 6:11pm.

-Draw a diagram of this scenario and label the parts with the different physics concepts in play.

-Determine the horizontal distance travelled by the block after falling off the table.

-What is the final velocity of the block.

-At what angle does the block hit the ground? (relative to the horizontal)

-How much time is elapsed between the bullet hitting the block and the block striking the ground?

- physics -
**Damon**, Wednesday, January 16, 2013 at 6:27pm.04 kg bullet + 0.3 kg block = .34 kg final

initial momentum = momentum after collision

2.8 = .34 v

v = 8.24 m/s sliding along table

That is the horizontal velocity component until it hits the floor

How long to fall ?

h = (1/2) g t^2

2 = 4.9 t^2

t = .639 seconds falling

how far horizontal in .639 seconds

x = u t = 8.24 * .639 = 5.26 meters

vertical speed component

v = g t = 9.81 (.639) = 6.27 m/s

so velociy is 8.24 i - 6.27 j

speed =sqrt(8.24^2 + 6.27*2)

= 10.35 meters/second

tan angle below horizontal = 6.27/8.24

so angle = 37.3 degrees below horizontal

how long on table

15 meters/8.24

= 1.82 seconds on table

+ .639 in air

= 2.46 seconds

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