physics
posted by k on .
A 91.0 N grocery cart is pushed 17.1 m along an aisle by a shopper who exerts a constant horizontal force of 42.0 N. The acceleration of gravity is 9.81 m/s2 .
If all frictional forces are neglected and the cart starts from rest, what is the grocery cartâ€™s final speed? Answer in units of m/s

m*g = 91 N.
m = 91/g = 91/9.81 = 9.29 kg.
a = Fap/m = 42/9.29 = 4.52 m/s^2.
V^2 = Vo^2 + 2a*d.
V^2 = 0 + 9.05*17.1 = 154.69
V = 12.44 m/s. = Final velocity.