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March 25, 2017

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An aircraft maintains a speed of 500 miles per hour in a southwestern direction. The velocity of the jet stream is constant 50 miles per hour from the west. Find the resultant vector, the speed, and actual direction of the aircraft.

  • trig - ,

    R = 500mi/h @ 225o + 50mi/h @ 0o

    X = 500*cos225 + 50 = --303.6/303.6 mi/h.
    Y = 500*sin225 = -353.6 mi/h.

    tanAr = Y/X = -353.6/-303.6 = 49.35o =
    Reference Angle.
    A = 49.35 + 180 = 229.35o,CCW = 40.65o
    West of South = Direction.

    V = X/cosA = -303.6/cos229.35=466 mi/h.

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