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March 30, 2015

March 30, 2015

Posted by **Deb** on Tuesday, January 15, 2013 at 6:23pm.

- trig -
**Henry**, Thursday, January 17, 2013 at 10:16pmR = 500mi/h @ 225o + 50mi/h @ 0o

X = 500*cos225 + 50 = --303.6/303.6 mi/h.

Y = 500*sin225 = -353.6 mi/h.

tanAr = Y/X = -353.6/-303.6 = 49.35o =

Reference Angle.

A = 49.35 + 180 = 229.35o,CCW = 40.65o

West of South = Direction.

V = X/cosA = -303.6/cos229.35=466 mi/h.

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