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July 31, 2014

July 31, 2014

Posted by **Lisa** on Tuesday, January 15, 2013 at 2:38pm.

3cos(t) + 3*sqrt(3)*sin(t)=6cos(t-x)

I know that 6 cos(t-x) can be 6(cos(t)cosx(x)+sin(t)sin(x))

I dont know where to go from there though.

- Calculus -
**Steve**, Tuesday, January 15, 2013 at 2:45pmwhat you have now is

3cost + 3√3 sint = 6cosx cost + 6sinx sint

for them to be identical, the coefficients must match:

3 = 6cosx

3√3 = 6sinx

looks like x = π/3

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