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March 6, 2015

March 6, 2015

Posted by **Lisa** on Tuesday, January 15, 2013 at 2:08pm.

1)e^(i*pi) + 2e^(i*pi/4)=?

2)3+3=3i*sqrt(3)=xe^(i*pi/3)

MY attempt:

I'm not really sure of what they are asking.

For the 1st one I used the e^ix=cos(x)+i*sin(x)

and got -1+sqrt(2) +sqrt(2)i

2) I solved for x and fot (3+3i*sqrt(3))/(1/2+i*sqrt(3)/2)

- Calculus -
**Steve**, Tuesday, January 15, 2013 at 2:21pmyour 1st answer is correct

#2.

x(1/2 + √3/2 i) = 3+3i√3

x = (3+3√3 i))/[1/2 (1+√3 i)]

now rationalize by multiplying by conjugate

x = 3(1+√3 i)* 2(1-√3 i)/(1-3)

x = -3(1+√3 i))(1-√3 i)

x = -3(1-3)

x = 6

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