Write the balanced equation of the reaction described below. Include the states (s, l, aq, g) for the reactants and products.

When aqueous calcium chloride and sodium phosphate are mixed, solid calcium phosphate and acqueous sodium chloride are produced.

CaCl2 (aq) + Na3PO4 (s) >> Ca3(PO4)2 (s) + NaCl (aq)

Balancing it is easy. go to the most complicated formula, and wort from there.

it is Ca3(PO4)2

so you need three Ca on left then.

3 CaCl2 + Na3PO4 >> Ca3(PO4)2 + NaCl

Now consider the phosphates in the complicated calcium phosphate: two of them.

3CaCl2 + 2Na3PO4 >> Ca3(PO4)2 + NaCl
now clean it up. first, Cl
you need two Cl in NaCl...
3CaCl2 + 2Na3PO4 >> Ca3(PO4)2 + 2NaCl
done. reinsert the states from above.

but that's wrong because sodium is not balanced

Right. You need six NaCl. sometimes we introduce obvious errors to keep student from copying and pasting.

Good work.

but that's my problem I don't know how to get Na balanced

To write the balanced equation for this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

First, let's write the chemical formulas for the reactants and products based on the given information:

Reactants:
Aqueous calcium chloride: CaCl2 (aq)
Sodium phosphate: Na3PO4 (aq)

Products:
Solid calcium phosphate: Ca3(PO4)2 (s)
Aqueous sodium chloride: NaCl (aq)

Now, we can write the balanced equation:

3 CaCl2 (aq) + 2 Na3PO4 (aq) → Ca3(PO4)2 (s) + 6 NaCl (aq)

In this balanced equation, we have three calcium chloride molecules reacting with two sodium phosphate molecules to produce one molecule of solid calcium phosphate and six molecules of sodium chloride.

Make sure to balance the equation by adjusting the coefficients in front of the formulas to ensure the same number of each type of atom on both sides of the equation.