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March 3, 2015

March 3, 2015

Posted by **Krissy** on Tuesday, January 15, 2013 at 12:34pm.

1. Simplify the expression using the quotient to a power property. (3y^6/z^7)^3

a. 27y^9/z^7

b. 3y^9/z^10

c. 27y^18/z^7

d. 27y^18/z^21

2. Use a descriptive variable and an inequality symbol to write a model for the statement. The Thompson family will spend more than 14,000 on home improvement.

a. Let a represent the amount. a < $14,000

b. Let a represent the amount. a < $14,000

c. Let a represent the amount. a > $14,000

d. Let a represent the amount. a > $14,000

3. Simplify and subtract (if possible). 1027x-75x

a. 253x

b. 1048x

c. 25x3

d. Cannot be subtracted

4. Rewrite the expression as a single term. 1/r-1/s+1/t

a. St+rt-rs/r-s+t

b. 1/r-s+t

c. St+rt-rs/rst

d. St-rt+rs/rst

5. Factor the difference of perfect cubes completely. 27a^3-1000

a. (3a+10)(9a^2-100)

b. (3a-10)(9a^2+100)

c. (3a+10)(9a^2-30a+100)

d. (3a-10)(9a^2+30a+100)

- College Algebra -
**Steve**, Tuesday, January 15, 2013 at 2:42pm(3y^6/z^7)^3

3^3 (y^6)^3 / (z^7)^3

27 y^18/z^21

(D)

"more than" means greater

don't know why a&b and c&d are the same, but (C) or (D) works for me. I assume there should have been <= or >= in there. You want just ">" since we want "more," not just "at least".

10√27x-√75x

10√9√3x - √25√3x

10*3√3x - 5√3x

25√3x

(A)

1/r-1/s+1/t

put over a common denominator: rst

st/rst - rt/rst + rs/rst

(st-rt+rs)/(rst)

(D) assuming the usual sloppiness with parentheses

27a^3-1000

(3a)^3 - 10^3

(3a-10)(9a^2+30a+100)

(D)

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