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September 30, 2014

September 30, 2014

Posted by **Anonymous** on Tuesday, January 15, 2013 at 11:22am.

Find in terms of t, the co-ordinates of P

- maths-urgently needed -
**Steve**, Tuesday, January 15, 2013 at 11:41amP has coordinates (x,tx)

The line from (3,0) to P has slope -1/t

now, drop an altitude from P to the x-axis.

tx/(x-3) = -1/t

x = 3/(1+t^2)

P = (3/(1+t^2), 3t/(1+t^2))

- maths-urgently needed -
**bobpursley**, Tuesday, January 15, 2013 at 11:42amline 1: y=tx

line 2: y=-x/t +b

but you know point 3,0 is on line 2

0=-3/t + b or b=3/t

line2: y=-x/t +3/t

line1 y=tx

set them equal

tx=-x/t+3/t solve for x

then solve for y.

- maths-urgently needed -
**Anonymous**, Tuesday, January 15, 2013 at 12:19pmThank u so much @steve and @bobpursley

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