College Algebra
posted by Krissy on .
I have a few more questions that I'm not understanding. Its multiple choice however I would appreciate a breakdown on how to solve.
1.Evaluate without a calculator, using the order of operations. 2^2+20820squareroot of 64
a. 36
b. 4
c. 28
d. 4
2.Simplify the expression. Square root of 16
a. 4
b. 4
c. 8
d. Not a real number

2^2+20820squareroot of 64
= 4 + 20  12  8
= 4
√16 > not a real number
( in your first one, notice the difference between
2^2 and (2)^2 ) 
2^2+20820√64
4+20128
4+20128
4
(D)
since x^2 >= 0 for all real x,
(D)
√16 = 4i, a complex number