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Posted by on Tuesday, January 15, 2013 at 8:00am.

The length of the rectangle is 4 more than twice its width and its perimeter is 70m. What are the dimensions of the rectangle?

  • Geometry - , Tuesday, January 15, 2013 at 8:12am

    let x = witdth
    4x+2 = length

    perimeter of rectangle = 2L + 2W
    substitute:
    34 = 2(4x+2) +2x
    34 = 8x + 4 + 2x
    34-4 = 10x
    10x = 30
    x = 3 - width

    length = 4(3) + 2
    = 12 + 2 = 14 :)

  • Geometry - , Tuesday, January 15, 2013 at 8:57am

    John, why isn't the length 2x + 4 ??

  • Geometry - , Tuesday, January 15, 2013 at 10:00am

    Good catch
    John has his definition backwards, thus his answer is not correct

    width --- x
    length ---- 2x+4

    2x + 2(2x+4) = 70
    6x + 8 = 70
    6x = 62
    x = 31/3 or 10 1/3

    width = 31/3
    length = 2(31/3)+4 = 74/3 or 24/2/3

    check: 2(31/3) + 2(74/3) = 70

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