Posted by **Anonymous** on Tuesday, January 15, 2013 at 8:00am.

The length of the rectangle is 4 more than twice its width and its perimeter is 70m. What are the dimensions of the rectangle?

- Geometry -
**John**, Tuesday, January 15, 2013 at 8:12am
let x = witdth

4x+2 = length

perimeter of rectangle = 2L + 2W

substitute:

34 = 2(4x+2) +2x

34 = 8x + 4 + 2x

34-4 = 10x

10x = 30

x = 3 - width

length = 4(3) + 2

= 12 + 2 = 14 :)

- Geometry -
**Writeacher**, Tuesday, January 15, 2013 at 8:57am
John, why isn't the length 2x + 4 ??

- Geometry -
**Reiny**, Tuesday, January 15, 2013 at 10:00am
Good catch

John has his definition backwards, thus his answer is not correct

width --- x

length ---- 2x+4

2x + 2(2x+4) = 70

6x + 8 = 70

6x = 62

x = 31/3 or 10 1/3

width = 31/3

length = 2(31/3)+4 = 74/3 or 24/2/3

check: 2(31/3) + 2(74/3) = 70

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