Posted by Anonymous on Tuesday, January 15, 2013 at 8:00am.
The length of the rectangle is 4 more than twice its width and its perimeter is 70m. What are the dimensions of the rectangle?

Geometry  John, Tuesday, January 15, 2013 at 8:12am
let x = witdth
4x+2 = length
perimeter of rectangle = 2L + 2W
substitute:
34 = 2(4x+2) +2x
34 = 8x + 4 + 2x
344 = 10x
10x = 30
x = 3  width
length = 4(3) + 2
= 12 + 2 = 14 :)

Geometry  Writeacher, Tuesday, January 15, 2013 at 8:57am
John, why isn't the length 2x + 4 ??

Geometry  Reiny, Tuesday, January 15, 2013 at 10:00am
Good catch
John has his definition backwards, thus his answer is not correct
width  x
length  2x+4
2x + 2(2x+4) = 70
6x + 8 = 70
6x = 62
x = 31/3 or 10 1/3
width = 31/3
length = 2(31/3)+4 = 74/3 or 24/2/3
check: 2(31/3) + 2(74/3) = 70
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