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March 26, 2017

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log base b 64 - log base b 16 = log base 4 16
solve for the variable..

i got to the part as far as:

(log 4/log b) = 2

now i m stuck at how i can isolate the b. plz help!

  • Trig - ,

    look at your right side
    isn't log4 16 = 2 ???

    so you have:
    logb 64 - logb16 = 2
    logb(64/16) = 2
    logb 4 = 2
    or
    b^2 = 4
    b = 2

    from your:

    log4/logb = 2
    cross-multiply
    log4 = 2logb
    log4 = log b^2
    then 4 = b^2
    b = 2 , just like above

  • Trig - ,

    log b (4) = 2

    b^log b( 4) = 4

    so b^logb(4) = b^2
    so
    b^2 = 4

    b = 2

  • Trig - ,

    Ohh alright! Thank you :)

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