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Posted by on Monday, January 14, 2013 at 8:03pm.

solve sin theta = 1/2,90 degrees less than theta less than 180 degrees

  • math pre calc - , Monday, January 14, 2013 at 8:44pm

    make sure your calculator is set to degrees

    2nd
    sin
    (1/2.9)
    = 20.17

    You want the angle between 0 and 180, that is in the I or II quadrant.
    20.17° is in quadrant I
    the angle in quadrant II would be 180 - 20.17 = 159.83°

    check:
    take the sine of each of those angles and compare it to 1/2.9

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