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March 4, 2015

March 4, 2015

Posted by **tami** on Monday, January 14, 2013 at 2:14pm.

m/s from east to west and the other is a 40 kg going from south to north at 12 m/s.

(a) Find the x and y components of the net momentum of this system.

(b) What are the magnitude and direction of the net momentum

- physics -
**Henry**, Wednesday, January 16, 2013 at 7:27pma. X = m1V1 = 50 * -8 = -400.

Y = m2V2 =40 * 12 = 480.

b. tanA = Y/X = 480/-400 = -1.20.

Ar = -50.19 = Reference angle.

A = -50.19 + 180 = 129.8o = Direction.

Magnitude = X/cosA = -400/cos129.8 = 625.

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