A bag is dropped from a hovering helicopter. The bag has fallen for 1.8 s. What is the bag's velocity?

How far has the bag fallen?

V = g*t

distance fallen = (g/2)*t^2

To find the velocity of the bag, we can use the equation:

v = g * t

Where:
v = velocity (m/s)
g = acceleration due to gravity (9.8 m/s^2)
t = time (s)

Substituting the given values:
v = 9.8 m/s^2 * 1.8 s
v ≈ 17.64 m/s

Therefore, the bag's velocity is approximately 17.64 m/s.

To find how far the bag has fallen, we can use the equation:

d = (1/2) * g * t^2

Where:
d = distance fallen (m)

Substituting the given values:
d = (1/2) * 9.8 m/s^2 * (1.8 s)^2
d ≈ 15.876 m

Therefore, the bag has fallen approximately 15.876 meters.

To find the bag's velocity when it has fallen for 1.8 seconds, we can use the formula for free fall:

v = gt

where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and t is the time.

Plugging in the values, we get:

v = (9.8 m/s^2) * (1.8 s)
v = 17.64 m/s

So the bag's velocity after falling for 1.8 seconds is 17.64 m/s.

To find how far the bag has fallen, we can use another formula for free fall:

d = 1/2 * g * t^2

where d is the distance, g is the acceleration due to gravity, and t is the time.

Plugging in the values, we get:

d = 1/2 * (9.8 m/s^2) * (1.8 s)^2
d = 1/2 * (9.8 m/s^2) * (3.24 s^2)
d = 15.876 m

So the bag has fallen approximately 15.876 meters.

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