A bag is dropped from a hovering helicopter. The bag has fallen for 1.8 s. What is the bag's velocity?
How far has the bag fallen?
V = g*t
distance fallen = (g/2)*t^2
To find the velocity of the bag, we can use the equation:
v = g * t
Where:
v = velocity (m/s)
g = acceleration due to gravity (9.8 m/s^2)
t = time (s)
Substituting the given values:
v = 9.8 m/s^2 * 1.8 s
v ≈ 17.64 m/s
Therefore, the bag's velocity is approximately 17.64 m/s.
To find how far the bag has fallen, we can use the equation:
d = (1/2) * g * t^2
Where:
d = distance fallen (m)
Substituting the given values:
d = (1/2) * 9.8 m/s^2 * (1.8 s)^2
d ≈ 15.876 m
Therefore, the bag has fallen approximately 15.876 meters.
To find the bag's velocity when it has fallen for 1.8 seconds, we can use the formula for free fall:
v = gt
where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and t is the time.
Plugging in the values, we get:
v = (9.8 m/s^2) * (1.8 s)
v = 17.64 m/s
So the bag's velocity after falling for 1.8 seconds is 17.64 m/s.
To find how far the bag has fallen, we can use another formula for free fall:
d = 1/2 * g * t^2
where d is the distance, g is the acceleration due to gravity, and t is the time.
Plugging in the values, we get:
d = 1/2 * (9.8 m/s^2) * (1.8 s)^2
d = 1/2 * (9.8 m/s^2) * (3.24 s^2)
d = 15.876 m
So the bag has fallen approximately 15.876 meters.