two poles are of height 20 metres and 14 metres. the wire makes an angle of 30 degree with the horizontal. find the distance between the twopoles.
tan30=6/BC
tan30=6/BC OR,BC=6/TAN30 =6/1/ROOT3 =6X1.732 =10.392
To find the distance between the two poles, we can use trigonometry. We will consider the 20-meter pole as the taller pole and the 14-meter pole as the shorter pole.
We can form a right-angled triangle with the horizontal, the wire, and the distance between the two poles as the hypotenuse.
Let's denote the distance between the two poles as 'd.'
Using trigonometry, we can establish the following relationship:
sin(30°) = opposite/hypotenuse
The opposite side in this case would be the height of the shorter pole, which is 14 meters. The hypotenuse would be the distance between the two poles, denoted as 'd.'
sin(30°) = 14/d
To isolate 'd,' we can rearrange the equation:
d = 14/sin(30°)
Now, we can calculate the value of sin(30°). The sine of 30 degrees is 0.5.
d = 14/0.5
d = 28 meters
Therefore, the distance between the two poles is 28 meters.