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October 30, 2014

October 30, 2014

Posted by **mathstudent205** on Monday, January 14, 2013 at 8:38am.

May I ask you a big favor?

I need help.

What I have is:

A bag contains marbles of three different colors with at least three marbles of each color.

Three marbles are randomly selected, without replacement. How many different color combinations are possible?

I tried to use Combinatorial Calculator here:

numberempire com

And I've got : 10

Seems like it is the right answer, because textbook shows me the same..

But I want to understand the way of solving it.

Please show me step by step solution or the formula.

Thanks in advance.

- Math -
**Reiny**, Monday, January 14, 2013 at 9:08amIt said, "How many different color combinations are possible" , so as long as there are 3 different colours available, the number of actual marbles does not matter.

Suppose we have R, B , and G for our colours.

So we could have:

RRR

RRB

RRG

BBB

BBR

BBG

GGG

GGR

GGB

RBG ----> which makes 10

or

all the same = 3

2 of one, the third different = (3x1)x2 = 6

all different = 1

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