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October 1, 2014

October 1, 2014

Posted by **Dani mak** on Monday, January 14, 2013 at 1:31am.

- Derivatives -
**Reiny**, Monday, January 14, 2013 at 8:36amMake a sketch of their current position, placing B at the origin and A on the negative x-axis, 70 units from the origin

At a time of t hours, let the position of Ship A be A1 and the position of ship B be B1

Now AA1 = 25t km , and BB1 = 45t km

Join A1B1

Extend A1A upwards to C and complete the right-angled triangle,

with A1C = 25t+45t = 70t, CB1 = 70 , and hypotenuse A1B1 as the distance between the two ships.

let that distance be h

h^2 = (70t)^ + 70^2

h^2 = 4900t^2 + 4900

2h dh/dt = 9800t dt/dt = 9800t

when t = 2

h^2 = 140^2+70^2

...

h =√24500 = appr 156.525 km

at t=2

dh/dt = 9800(2)/(2√24500)

= 62.61 km/h

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