Tuesday

October 21, 2014

October 21, 2014

Posted by **Emily** on Sunday, January 13, 2013 at 10:04pm.

the end of a 1.2 m chain in a horizontal circle.

The hammer moves at the rate of 0.432 rev/s.

What is the centripetal acceleration of the

hammer? Assume his arm length is included

in the length given for the chain.

Answer in units of m/s

2

What is the tension in the chain?

Answer in units of N

- physics -
**Jennifer**, Tuesday, January 15, 2013 at 8:44pmcentripetal acceleration is v^2/r

The tension in the chain is m*v^2/r

where v is the speed = 2*PI*r*f

where f is the frequency; r is the radius; m is the mass

v = 2*PI*1.2*0.432

solve for the acceleration and tension using the above equations

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