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March 28, 2017

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Two forces are applied to a car in an effort to accelerate it, as shown below. The first force, F1 = 364 N, is applied at an angle α = 33° to the forward dashed line. The second force, F2 = 522 N, is applied at an angle β = 11° to the forward dashed line.
What is the resultant of these two forces?
in N and at what degree
If the car has a mass of 3050 kg, what acceleration does it have? (Disregard friction.)
in m/s2 at what degree

  • Physics - ,

    Take components of the force:

    F1x = 364*cos(33)
    F1y = 364*sin(33)

    F2x = 522*cos(11)
    F2y = 522*sin(11)

    Fnetx = F1x + F2x
    Fnety = F1y + F2y

    Fnet = ((Fnetx)^2 + (Fnety)^2)^0.5

    at an angle theta given by

    tan(theta) = Fnety/Fnetx

    where Fnet = m*a = 3050*a

    Solve for a, the acceleration

  • Physics - ,

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