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December 21, 2014

December 21, 2014

Posted by **Kristen** on Sunday, January 13, 2013 at 7:18pm.

The whole problem is

x^2-7x-18/x^2-6x-27*2x^2+7x+2/2x^2+5x+2

- College Algebra -
**Reiny**, Sunday, January 13, 2013 at 8:52pm2x^2 + 7x + 2 does not factor using rational numbers.

Here is how I know

Multiply the first times the last ---> 2(2) = 4

Are there two numbers which when multiplied will give you 4 and which added will give you 7 ?

Nope!

I think your problem is meant to say:

(x^2-7x-18)/(x^2-6x-27) * (2x^2+7x+2)/(2x^2+5x+2)

HUGE difference from what you wrote

= (x-9)(x+2)/((x-9)(x+3) * (2x^2 + 7x + 2)/((2x+1)(x+2))

= (2x^2 + 7x + 2)/((x+3)(2x+1))

notice that if we expand the bottom we get

2x^2 + 7x + 3

are you sure you don't have a typo in the top and that 2 is not a 3 ????

If not, the book probably has that typo.

- College Algebra -
**Kristen**, Monday, January 14, 2013 at 12:28pmYes it was a typo it was a 3! Thanks for the help this does make scense.

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