Posted by Anon on Sunday, January 13, 2013 at 7:05pm.
Is it because it only has four electrons to begin with with only two valence electrons? There's no way it can possible even make an octet?
Yes but BeH2 is not that common. I think BeCl2 is a better example. Boron is another that breaks the octet rule; e.g., BF3.
Be and B are the huge ones on breaking the octet rule. But, for that question they gave BeH2 so, I guess reasoning is that they are the exceptions? It's multiple choice. but I still want to understand it.
H:Be:H
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