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December 18, 2014

December 18, 2014

Posted by **gary** on Sunday, January 13, 2013 at 4:35pm.

2. x=y^3/3y^2+y/2,what is the value of y in terms of x ?

- math -
**Reiny**, Sunday, January 13, 2013 at 5:03pm1. I think you meant:

x = (3y-2)/4

if so, then

.... times 4

4x = 3y - 2

4x + 2 = 3y

y = (4x+2)/3

2. I will take your question the way you typed it except I think your denominator for the first fraction is probably 3y^2, so it needs brackets

x = (1/3) y + y/2

times 6

6x = 2y + 3y

6x = 5y

y = 6x/5

- math -
**john**, Sunday, January 13, 2013 at 5:23pmthank you, Reiny

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