Posted by **Anonymous** on Sunday, January 13, 2013 at 10:46am.

Suppose

a+4b+9c+16d+25e=-13,

4a+9b+16c +25d +36e =-8,

9a+16b+25c+36d+49e=3,

Find the value of

16a+25b+36c+49d+64e=?

- maths-urgent -
**drwls**, Sunday, January 13, 2013 at 11:20am
Are you sure your third equation is not

9a+ 16b+ 25c +36d +49e = -3 ?

Then it would fall into a certain pattern with the others.

16a +25b +36c +49d +64e = +2

In general, your first three equations in five unknowns have an infinite number of possible solutions, so that the fourth equation cannot be solved uniquely

- maths-urgent -
**confused**, Sunday, January 13, 2013 at 11:24am
price of a home is 164,000. bank requires a 20% down payment and 3 points at closing. the cost of the home is financed with a 30 year fixed rate mortgage at 9%

- note to "confused" -
**drwls**, Sunday, January 13, 2013 at 11:33am
Use "Post a New Question". Do not add yours to someone else's discussion thread.

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