Posted by Anonymous on Sunday, January 13, 2013 at 10:46am.
Suppose
a+4b+9c+16d+25e=13,
4a+9b+16c +25d +36e =8,
9a+16b+25c+36d+49e=3,
Find the value of
16a+25b+36c+49d+64e=?

mathsurgent  drwls, Sunday, January 13, 2013 at 11:20am
Are you sure your third equation is not
9a+ 16b+ 25c +36d +49e = 3 ?
Then it would fall into a certain pattern with the others.
16a +25b +36c +49d +64e = +2
In general, your first three equations in five unknowns have an infinite number of possible solutions, so that the fourth equation cannot be solved uniquely 
mathsurgent  confused, Sunday, January 13, 2013 at 11:24am
price of a home is 164,000. bank requires a 20% down payment and 3 points at closing. the cost of the home is financed with a 30 year fixed rate mortgage at 9%

note to "confused"  drwls, Sunday, January 13, 2013 at 11:33am
Use "Post a New Question". Do not add yours to someone else's discussion thread.