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A 200kg turtle running at a speed of .4m/s jumps onto a stationary skateboard that masses 3.6kg. the turtle slows to .2m/s by shooting the skateboard out from under him. how fast is the skateboard moving as a result?

  • physics - ,

    After the turtle jumps on, conservation of momentum tells you that the velocity of both (V) is
    200*0.4 = (200 +3.6)V
    V = 0.393 m/s

    To slow down the turtle to 0.2 m/s by shooting the skateboard forward, the skateboard achieves velocity v given by
    203.6*0.393 = 200*0.2 + 3.6 v
    3.6 v= 80.0 -40.0 = 40.0
    v = 11.1 m/s

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